1989
DOI: 10.1016/0378-3812(89)80262-6
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Solid-liquid-gas equilibria in multicomponent supercritical fluid systems

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Cited by 71 publications
(48 citation statements)
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“…normally 122.5"C; however, in the presence of a SCF this can be lowered significantly. In the presence of pure C02, 2-naphthol's melting point is lowered to 107°C at 210 bar; with C 0 2 and 4% methanol, the melting point is lowered to 63°C at 204 bar, and 43°C at 107 bar (Lemert and Johnston, 1989). In both cases, the UCEP was over 200 bar.…”
Section: Resultsmentioning
confidence: 96%
See 1 more Smart Citation
“…normally 122.5"C; however, in the presence of a SCF this can be lowered significantly. In the presence of pure C02, 2-naphthol's melting point is lowered to 107°C at 210 bar; with C 0 2 and 4% methanol, the melting point is lowered to 63°C at 204 bar, and 43°C at 107 bar (Lemert and Johnston, 1989). In both cases, the UCEP was over 200 bar.…”
Section: Resultsmentioning
confidence: 96%
“…Despite the great potential of using cosolvents, there are relatively few data in the literature for solubility of solutes in mixed SCF's (Dobbs et al, 1986;Schmitt and Reid, 1986;Wong and Johnston, 1986;Van Alsten, 1986;Schaeffer et al, 1988;Lemert and Johnston, 1989;Tavana et al, 1989;Cygnarowicz et al, 1990;Hollar and Ehrlich, 1990;Smith and Wormald, 1990;Gurdial and Foster, 1991). One reason is that conventional techniques of measuring solubilities in SCF solutions are timeconsuming and require large amounts of pure solute.…”
Section: Introductionmentioning
confidence: 96%
“…Examples of tie lines that extend to a binary axis are described by Walas (1985). Schematic tie lines are shown to the right of the three-phase region, although such lines could be calculated with a model in the literature (Lemert and Johnston, 1989). These tie lines emanate from the pure naphthalene vertex as described previously (Koningsveld and Diepen, 1983).…”
Section: Predicted Ternary-phase Behavior At Finite Concentration Fromentioning
confidence: 99%
“…Thus, a single fluid phase with y 2 = ψ 2 is next postulated, and this is tested for phase stability as described above. If the test indicates stability, then the equilibrium state is a single fluid phase with y 2 = ψ 2 ; otherwise two fluid phases are next postulated, and we again initiate the two-stage 21 procedure described in section 3.3 that alternates between phase split and phase stability calculations until the correct number of phases and phase compositions are found.…”
Section: Problem-solving Strategymentioning
confidence: 99%