Trends in Mathematics
DOI: 10.1007/978-3-7643-8412-8_10
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Solution of the Membership Problem for Magnus Subgroups in Certain One-Relator Free Products

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“…?/, and hence proves Theorem C. We remark that it also implies several results of different nature. In [Ju5] we solved the membership problem for Magnus subgroups of one-relator free products with small cancellation. In [Ju6] we proved the appropriate version of Magnus's Freiheitssatz for Magnus subsemigroups of one-relator groups with small cancellation.…”
Section: Moreover If R Has No Cyclic Conjugate R As Inmentioning
confidence: 99%
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“…?/, and hence proves Theorem C. We remark that it also implies several results of different nature. In [Ju5] we solved the membership problem for Magnus subgroups of one-relator free products with small cancellation. In [Ju6] we proved the appropriate version of Magnus's Freiheitssatz for Magnus subsemigroups of one-relator groups with small cancellation.…”
Section: Moreover If R Has No Cyclic Conjugate R As Inmentioning
confidence: 99%
“…The next section is devoted to the improved version of Greendlinger's Lemma. A similar version was formulated in [Ju5] the proof of which, using Lemmas 2.3 and 2.11, easily can be adapted to the proof of Proposition 2.12 below. Therefore, we shall omit the details of the proof, which consists of case by case checking.…”
Section: Thenˆá/ Contains No Cyclic Conjugate Of A˙1mentioning
confidence: 99%