1964
DOI: 10.1090/s0002-9939-1964-0161070-x
|View full text |Cite
|
Sign up to set email alerts
|

Some Hausdorff matrices not of type M

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1

Citation Types

0
6
0

Year Published

1967
1967
2011
2011

Publication Types

Select...
7
1

Relationship

0
8

Authors

Journals

citations
Cited by 9 publications
(6 citation statements)
references
References 3 publications
0
6
0
Order By: Relevance
“…B is obtained by removing the first row and first column from A -a oo l. Therefore B = U*DU. By Theorem 1 of [4], D is not of type M, and a suitable sequence t is t 0 = 1, t n = (-ϊ) n ε(e -1) (e -n + l)/n I n > 0. Therefore B is also not of type M.…”
Section: =1mentioning
confidence: 99%
“…B is obtained by removing the first row and first column from A -a oo l. Therefore B = U*DU. By Theorem 1 of [4], D is not of type M, and a suitable sequence t is t 0 = 1, t n = (-ϊ) n ε(e -1) (e -n + l)/n I n > 0. Therefore B is also not of type M.…”
Section: =1mentioning
confidence: 99%
“…(2) (U*) n+1 (A -a n J)U n+1 of type M for each n is equivalent to 618 (1). This assertion is false.…”
mentioning
confidence: 97%
“…In [2] it is shown that, for A a conservative triangle, B a matrix with finite norm commuting with A, B is triangular if and only if (1) for each tel and each n, t(Aa nn I) -0 implies t belongs to the linear span of (β 0 , e u •••, e n ). On page 716 of [2] it is asserted that…”
mentioning
confidence: 99%
See 1 more Smart Citation
“…We can regard H as the product of two Hausdorίf matrices H a and H β , with generating sequences a n = (n -1/2)/(n + 1) and β n = n/{n + 2), respectively. From Theorem 1 of [1], the sequence t = {t n }, with t 0 = 1; t n = (-l) % (l/2)(-3/2). -(-n + 3/2)/%!, n > 0 satisfies ίfi α = 0.…”
mentioning
confidence: 99%