2013
DOI: 10.4064/cm130-2-1
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Some notions of amenability for certain products of Banach algebras

Abstract: For two Banach algebras A and B, an interesting product A × θ B, called the θ-Lau product, was recently introduced and studied for some nonzero characters θ on B. Here, we characterize some notions of amenability as approximate amenability, essential amenability, n-weak amenability and cyclic amenability between A and B and their θ-Lau product. Introduction. LetA and B be two Banach algebras and θ ∈ σ(B), the spectrum of B of all nonzero characters on B. Then the θ-Lau product of A and B, denoted by A × θ B, i… Show more

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Cited by 10 publications
(7 citation statements)
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“…Then by [3, Proposition 2.8.63 (i)], D| A = 0. Similar to [5], consider X as a closed linear subspace of A (2n) × T (2n) B (2n) spanned by…”
Section: Theorem 21 Let a And B Be Banach Algebras A Be Commutativementioning
confidence: 99%
See 1 more Smart Citation
“…Then by [3, Proposition 2.8.63 (i)], D| A = 0. Similar to [5], consider X as a closed linear subspace of A (2n) × T (2n) B (2n) spanned by…”
Section: Theorem 21 Let a And B Be Banach Algebras A Be Commutativementioning
confidence: 99%
“…for all (a, b), (a , b ) ∈ A × θ B. Amenability and weak forms of amenability of A × θ B studied in [5,9]. Let T : B → A be an algebra homomorphism, and A be a commutative Banach algebra.…”
mentioning
confidence: 98%
“…We recently have shown in [6] that if also A × θ B is approximately amenable, then A and B are approximately amenable. We have proved that the converse of this statement in general is not true; but, A × θ B is approximately amenable if A is amenable and B is approximately amenable.…”
Section: Introductionmentioning
confidence: 99%
“…Recently, several notions of amenability were first studied on A × θ B by Monfared [16] and then pursued by Vishki and Khoddami [5] and the authors [6].…”
Section: Introductionmentioning
confidence: 99%
“…11. If A is a weakly amenable commutative Banach algebra, then for any commutative Banach A-bimodule X we have H 1 (A, X ) = (0).…”
mentioning
confidence: 99%