2017
DOI: 10.1016/j.laa.2016.12.017
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Some properties of weighted operator means and characterizations of interpolational means

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Cited by 8 publications
(5 citation statements)
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“…Note that the condition in particular contains m 0 = l and m 1 = r. In [5] Fujii and Kamei constructed, given a symmetric operator mean σ, a regular continuous family of operator means {m α } α∈[0,1] in the following way: Am 2k+1 2 n+1 B := (Am k 2 n B)m(Amk+1 2 n B) for n, k ∈ N with 2k + 1 < 2 n+1 . The construction was extended by Pálfia and Petz [21] to an arbitrary (not necessarily symmetric) operator mean σ ( = l, r) in such a way that m s = σ when s = f ′ σ (1); see [24] for the equivalence between the two constructions for a symmetric σ. By Propositions 3.3 and 3.8 note also that if {m α } α∈[0,1] is such a regular continuous family, then so is the deformed {(m α ) σ } α∈[0,1] by any σ = l; for instance, {(!…”
Section: Properties and Examplesmentioning
confidence: 99%
See 3 more Smart Citations
“…Note that the condition in particular contains m 0 = l and m 1 = r. In [5] Fujii and Kamei constructed, given a symmetric operator mean σ, a regular continuous family of operator means {m α } α∈[0,1] in the following way: Am 2k+1 2 n+1 B := (Am k 2 n B)m(Amk+1 2 n B) for n, k ∈ N with 2k + 1 < 2 n+1 . The construction was extended by Pálfia and Petz [21] to an arbitrary (not necessarily symmetric) operator mean σ ( = l, r) in such a way that m s = σ when s = f ′ σ (1); see [24] for the equivalence between the two constructions for a symmetric σ. By Propositions 3.3 and 3.8 note also that if {m α } α∈[0,1] is such a regular continuous family, then so is the deformed {(m α ) σ } α∈[0,1] by any σ = l; for instance, {(!…”
Section: Properties and Examplesmentioning
confidence: 99%
“…It was shown in [4, Theorem 1] that σ satisfies condition (ii) if and only if {m α } is an interpolation family. Then it follows from [24,Theorem 6]…”
Section: And Inductivelymentioning
confidence: 99%
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“…Then {σ λ } λ∈[0,1] should have the interpolatinal property [28,Theorem 4]. Moreover since σ λ is an operator mean, it should be the power mean by [28,Theorem 6]. 14…”
Section: A Problem -Norm Inequalitiesmentioning
confidence: 99%