By Descartes' rule of signs, a real degree d polynomial P with all nonvanishing coefficients, with c sign changes and p sign preservations in the sequence of its coefficients (c + p = d) has pos ≤ c positive and neg ≤ p negative roots, where pos ≡ c( mod 2) and neg ≡ p( mod 2). For 1 ≤ d ≤ 3, for every possible choice of the sequence of signs of coefficients of P (called sign pattern) and for every pair (pos, neg) satisfying these conditions there exists a polynomial P with exactly pos positive and exactly neg negative roots (all of them simple). For d ≥ 4 this is not so. It was observed that for 4 ≤ d ≤ 10, in all nonrealizable cases either pos = 0 or neg = 0. It was conjectured that this is the case for any d ≥ 4. We show a counterexample to this conjecture for d = 11. Namely, we prove that for the sign pattern (+, −, −, −, −, −, +, +, +, +, +, −) and the pair (1, 8) there exists no polynomial with 1 positive, 8 negative simple roots and a complex conjugate pair.