Abstract:In a recent paper [S. Doty, A. Henke, Decomposition of tensor products of modular irreducibles for SL 2 , Q. J. Math. 56 (2005) 189-207], Doty and Henke give a decomposition of the tensor product of two rational simple modules for the special linear group of degree 2 over an algebraically closed field of characteristic p > 0. In performing this calculation it proved useful to know that the simple modules are twisted tensor products of tilting modules. It seems natural therefore to consider the ring of twisted … Show more
“…As in Section 3, we identify X + (T ) n , X + (T ) ∞ , X + s (T ) n , X + s (T ) ∞ as subsets of X + (T ) × X + ( T ) ∞ in the usual way. By [ [4], p.no 72 (5)] and [ [4] (iii), (iv), (v) and (vi) follows from Proposition of Section 1 of [7].…”
Section: Now By [[7]mentioning
confidence: 99%
“…We let A C (n) = C ⊗ Z A n . By [7], we know that the polynomials Q p−1 (X i+1 − h(X i ))), i ≥ 0, has no repeated roots. Hence to show that the ring A C (n) is reduced, it is enough to show that (P l−1 (X −1 )(X 0 − g(X −1 )) has no repeated roots.…”
Section: Now By [[7]mentioning
confidence: 99%
“…If a 0 = 0, then (x 0 − (P l (b) − P l−2 (b)) is a zero divisor in A K (0). Now by [ [7], Section 3, Prop. ], for d = 1 and q = 1 and b = 2, we have (x 0 − 2) is a zero divisor which is not true.…”
Section: Statement Of Conflict Of Intereestmentioning
confidence: 99%
“…, where each Ti is an indecomposable tilting module of GL 2 (k). In a paper by [7], it has been shown that the ring of twisted tilting modules of SL 2 (k) is a reduced ring. In [8], it has been proved that the tensor product of any two simple quantum GL 2 (k)-modules can be expressed as a finite direct sum of twisted tilting modules.…”
Let G be the quantum GL n over a field of characteristic p = 0. In this paper we define the ring of twisted tilting modules of G. We give generators and relations for the ring of twisted tilting modules of quantum GL 2 (k). We also show that this is a reduced ring.
“…As in Section 3, we identify X + (T ) n , X + (T ) ∞ , X + s (T ) n , X + s (T ) ∞ as subsets of X + (T ) × X + ( T ) ∞ in the usual way. By [ [4], p.no 72 (5)] and [ [4] (iii), (iv), (v) and (vi) follows from Proposition of Section 1 of [7].…”
Section: Now By [[7]mentioning
confidence: 99%
“…We let A C (n) = C ⊗ Z A n . By [7], we know that the polynomials Q p−1 (X i+1 − h(X i ))), i ≥ 0, has no repeated roots. Hence to show that the ring A C (n) is reduced, it is enough to show that (P l−1 (X −1 )(X 0 − g(X −1 )) has no repeated roots.…”
Section: Now By [[7]mentioning
confidence: 99%
“…If a 0 = 0, then (x 0 − (P l (b) − P l−2 (b)) is a zero divisor in A K (0). Now by [ [7], Section 3, Prop. ], for d = 1 and q = 1 and b = 2, we have (x 0 − 2) is a zero divisor which is not true.…”
Section: Statement Of Conflict Of Intereestmentioning
confidence: 99%
“…, where each Ti is an indecomposable tilting module of GL 2 (k). In a paper by [7], it has been shown that the ring of twisted tilting modules of SL 2 (k) is a reduced ring. In [8], it has been proved that the tensor product of any two simple quantum GL 2 (k)-modules can be expressed as a finite direct sum of twisted tilting modules.…”
Let G be the quantum GL n over a field of characteristic p = 0. In this paper we define the ring of twisted tilting modules of G. We give generators and relations for the ring of twisted tilting modules of quantum GL 2 (k). We also show that this is a reduced ring.
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