2019
DOI: 10.2298/fil1914353t
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Some upper bounds for the Berezin number of Hilbert space operators

Abstract: In this paper, we obtain some Berezin number inequalities based on the definition of Berezin symbol. Among other inequalities, we show that if A, B be positive definite operators in B(H), and A B is the geometric mean of them, then ber 2 (A B) ≤ ber A 2 + B 2 2 − 1 2 inf λ∈Ω ζ(k λ), where ζ(k λ) = (A − B)k λ ,k λ 2 , andk λ is the normalized reproducing kernel of the space H for λ belong to some set Ω. A(λ) = Ak λ (z),k λ (z) ,

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Cited by 18 publications
(5 citation statements)
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“…which was given in [6]. This shows that Theorem 4.1 is an extension of the existing inequality (14).…”
Section: Ber(t ) =supporting
confidence: 58%
See 1 more Smart Citation
“…which was given in [6]. This shows that Theorem 4.1 is an extension of the existing inequality (14).…”
Section: Ber(t ) =supporting
confidence: 58%
“…For the basic properties and more facts about the Berezin norm and Berezin number, we refer the reader to [4,9,12,14] and the references therein.…”
Section: Ber(t ) =mentioning
confidence: 99%
“…It is clear from the definition that Ber(A) ⊆ W (A) and so ber(A) ≤ w(A). The Berezin symbols and Berezin number inequalities have been studied by many mathematicians over the years, for the latest and recent results we refer the readers to see [2,8,16,18,20,21,28,30] and the references therein.…”
Section: Introductionmentioning
confidence: 99%
“…It is clear from the definition that Ber(A) ⊆ W (A) and so ber(A) ≤ w(A). The Berezin number inequalities have been studied by many mathematicians over the years, for the latest and recent results we refer the readers to see [1,14,21,23] and the references therein.…”
Section: Introductionmentioning
confidence: 99%