2015
DOI: 10.1007/978-3-319-23660-5_18
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Specular Sets

Abstract: Abstract. We introduce specular sets. These are subsets of groups which 7 form a natural generalization of free groups. These sets are an abstract 8 generalization of the natural codings of interval exchanges and of linear 9 involutions. We prove several results concerning the subgroups generated 10 by return words and by maximal bifix codes in these sets.

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Cited by 5 publications
(5 citation statements)
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“…A specular set is then defined as a laminary set such that the extension graph of any nonempty word is a tree and the extension graph of the empty word has two connected components which are trees. Extensions of Theorem 6.4 and 6.9 are proved to hold in this context in [2]. This paper is organized as follows.…”
Section: Introductionmentioning
confidence: 99%
“…A specular set is then defined as a laminary set such that the extension graph of any nonempty word is a tree and the extension graph of the empty word has two connected components which are trees. Extensions of Theorem 6.4 and 6.9 are proved to hold in this context in [2]. This paper is organized as follows.…”
Section: Introductionmentioning
confidence: 99%
“…For example, what can we say about the subgroup of the free group generated by return words to a given word? In [5] it is proved that for minimal dendric sets, every set of return words is a basis of the free group, while in the case of specular sets, the set of return word to a fixed word is a basis of a particular subgroup called the even subgroup (see [4]).…”
Section: Resultsmentioning
confidence: 99%
“…The graph E 3 (a) is shown on the right. The tree sets of characteristic c ≥ 1 introduced in [4,11] give an example of eventually dendric shifts. Example 2.2 Let X be the shift generated by the morphism a → ab, b → cda, c → cd, d → abc.…”
Section: Eventually Dendric Shiftsmentioning
confidence: 99%
“…Note that we recover, as a particular case of Theorem 2 applied to the set X of words of length n in S, the fact that for a set S satisfying the hypotheses of the theorem, the factor complexity is p 0 = 1 and p n = n(Card(A) − χ(S)) + χ(S). Note that Theorem 2 has a converse (see [4]).…”
Section: Cardinality Theorem For Bifix Codesmentioning
confidence: 99%