“…( 12) is proportional to the integrated product signal, so that for maximal nuclear polarization, with p = 1, the product integrated intensity is increased by 50% compared to p = 0; also, in this case p zz = 1, and hence D(θ, φ) ∼ 1 − P 2 (cosθ) ∼ sin 2 θ. For the D-3 He reaction performed with p z ( 3 He) = 0.76 [34,35], p z (D, t = 1.5 ns) = 0.12 (reported here), and p zz (D) = 0, we predict a 14% variation in the angular distribution (between θ = 0 • and 90 • ) and a 4.5% increase in the integrated intensity, whereas if bond alignment is used prior to dissociation [36], p z (D, t = 1.5 ns) = 0.5 can be produced [8], leading to a 70% variation in the product angular distribution and a 19% increase in integrated intensity. In contrast, the effect of polarization in the D-D reaction is poorly understood, with predictions ranging from suppression to enhancement [3].…”