2017
DOI: 10.48550/arxiv.1706.03615
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Strichartz estimates for the metaplectic representation

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Cited by 2 publications
(3 citation statements)
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“…Step. We will show that (6) easily follows from (5). Indeed, the Fourier transform J = F is a metaplectic operator and we recall that the Fourier transform is a topological isomorphism F : [16].…”
Section: Thirdmentioning
confidence: 99%
See 1 more Smart Citation
“…Step. We will show that (6) easily follows from (5). Indeed, the Fourier transform J = F is a metaplectic operator and we recall that the Fourier transform is a topological isomorphism F : [16].…”
Section: Thirdmentioning
confidence: 99%
“…Comparing (4) and ( 5) we observe that in (5) the modulation operator M ξ is replaced by the metaplectic operator S and the integral on the phase space R 2n has become an integral on the cartesian product R n × U(2n, R). The integration parameters (x, ξ) of (4) live in R 2n , with dim R 2n = 2n, whereas the parameters (x, S) of ( 5) live in R n × U(2n, R).…”
Section: Introductionmentioning
confidence: 99%
“…As an application outside representation theory, we present some multidimensional dispersive estimates that go beyond the current fascination with dispersive estimates for the Schrödinger equation (see Tao [20] and also [6] for a representation theoretic perspective).…”
Section: Introductionmentioning
confidence: 99%