2022
DOI: 10.1016/j.jlumin.2021.118557
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Strong coupling effects in a plexciton system of gold nanostars and J-aggregates

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Cited by 18 publications
(8 citation statements)
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“…Note that because of intrinsic NUs’ size and shape distributions, the full‐width‐at‐half‐maximum of the extinction spectrum overestimates the γ NUs parameter, which may in turn lead to an underestimation of the coupling regime. [ 37 ] Notwithstanding, the abovementioned condition for the formation of hybrid plexciton states in the investigated nanohybrids remains strictly valid. This is a crucial point for the interpretation of the photophysical behavior of nanohybrids.…”
Section: Resultsmentioning
confidence: 99%
“…Note that because of intrinsic NUs’ size and shape distributions, the full‐width‐at‐half‐maximum of the extinction spectrum overestimates the γ NUs parameter, which may in turn lead to an underestimation of the coupling regime. [ 37 ] Notwithstanding, the abovementioned condition for the formation of hybrid plexciton states in the investigated nanohybrids remains strictly valid. This is a crucial point for the interpretation of the photophysical behavior of nanohybrids.…”
Section: Resultsmentioning
confidence: 99%
“…The ratio used to classify the interaction of type (iii) when the CL and the QEs had complementary interaction sites (usually opposite net charges). In contrast, interaction (iv) is assumed in the other cases, like for the CL/QEs pairs Styryl 9/M-SOt, JC1/cationic surfactant, and TDBC/PVP and TDBC/citrate . In some situations, interactions (iii) and (iv) are considered acting together. ,,, Interaction (iii) is assumed also in the case of dyes covalently linked to polymeric CLs .…”
Section: Resultsmentioning
confidence: 99%
“…The hybrid state should satisfy the condition of |α 2 + β 2 | = 1, which is nothing but the weighting coefficients of the fraction of Mie resonance mode (MQ/ED/AM) and exciton mode. The Hopfield coefficients can be determined using the following formula, α UEB = β LEB = ( E Mie E exc ) + false( E Mie E exc false) 2 + normalΩ normalR 2 2 false( E Mie 2 E exc 2 false) 2 + normalΩ normalR 2 α LEB = β UEB = 1 α UEB The energy of the hybrid state ( E UEB/LEB ) can be expressed as E UEB/LEB = 1 2 ( E Mie + E exc ) ± g 2 + 0.25 true( ( E …”
Section: Resultsmentioning
confidence: 99%
“…The hybrid state should satisfy the condition of |α 2 + β 2 | = 1, which is nothing but the weighting coefficients of the fraction of Mie resonance mode (MQ/ED/AM) and exciton mode. The Hopfield coefficients can be determined using the following formula, The energy of the hybrid state ( E UEB/LEB ) can be expressed as …”
Section: Resultsmentioning
confidence: 99%