1977
DOI: 10.1007/bf01215130
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Strongly annular functions with small Taylor coefficients

Abstract: A holomorphic function fin the unit disk D is strongly annular provided there exists a sequence {r,,} such that rm/" ! and lim min If(z)l = c~.The simplest examples of strongly annular functions have the form f(z)= ~ cmz km,(m=l where the sequence of coefficients % increases fast enough so that IClI+'"+Ic,,_II=O(Cm),

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Cited by 5 publications
(7 citation statements)
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“…(1) D. D. Bonar, F. Carroll, and G. Piranian [13,Theorem 1] proved that there exist positive numbers A 1 and A 2 such that for all k and n the coefficients b n 1/2 (k) satisfy the inequality…”
Section: 31mentioning
confidence: 99%
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“…(1) D. D. Bonar, F. Carroll, and G. Piranian [13,Theorem 1] proved that there exist positive numbers A 1 and A 2 such that for all k and n the coefficients b n 1/2 (k) satisfy the inequality…”
Section: 31mentioning
confidence: 99%
“…That is why Bonar asked in [11,Question 6.9] whether every strongly annular function is a sum of a bounded function and the sum of a lacunary Taylor series. In 1977 Bonar, Carroll, and Piranian [13] constructed a strongly annular function…”
Section: 31mentioning
confidence: 99%
See 1 more Smart Citation
“…R. W. Howell [8] has shown that under the topology of locally uniform convergence, a residual subset of the space of functions 2 e n z" (e n = ± 1) consists of strongly annular functions. Also, Bonar, Carroll, and Piranian [2] have proved that if the sequence {k n } increases rapidly enough, then the function n = l I I ' is strongly annular, although the sequence of its Taylor coefficients at the origin tends to 0.…”
Section: Strongly Annular Functionsmentioning
confidence: 99%
“…In Section 6, we saw that on the circle \z\ = r n = l-\/h n , the («+l)st term of the series in (1) has modulus less than 3. We shall now examine the modulus of the same term on the slightly larger circle \z\ = r n + \/h,, 2 . By elementary computations, By Lemma 1, we may assume that h n+l > 3h n 2 , so that on the circle \z\ = r n + l/h n 2 the (« + l)st term in (1) has modulus greater than exp /?".…”
Section: One-term Dominancementioning
confidence: 99%