2020
DOI: 10.1007/s43037-020-00084-9
|View full text |Cite
|
Sign up to set email alerts
|

Strongly irreducible factorization of quaternionic operators and Riesz decomposition theorem

Help me understand this report
View preprint versions

Search citation statements

Order By: Relevance

Paper Sections

Select...
2
1

Citation Types

0
3
0

Year Published

2021
2021
2024
2024

Publication Types

Select...
2
1

Relationship

0
3

Authors

Journals

citations
Cited by 3 publications
(3 citation statements)
references
References 19 publications
0
3
0
Order By: Relevance
“…First and foremost, we have by [4,Theorem 4.4] σ S (T ) = σ S (T 1 ) ∪ σ S (T 2 ) Take σ 1 = σ S (T 1 ) and σ 2 = σ S (T 2 ) and assume that dist(σ 1 , σ 2 ) > 0. According to the proof of [32,Theorem 6], there exist a pair of a non-empty disjoint axially symmetric domains (U σ 1 , U σ 2 ) such that…”
Section: Therefore (3)mentioning
confidence: 99%
See 1 more Smart Citation
“…First and foremost, we have by [4,Theorem 4.4] σ S (T ) = σ S (T 1 ) ∪ σ S (T 2 ) Take σ 1 = σ S (T 1 ) and σ 2 = σ S (T 2 ) and assume that dist(σ 1 , σ 2 ) > 0. According to the proof of [32,Theorem 6], there exist a pair of a non-empty disjoint axially symmetric domains (U σ 1 , U σ 2 ) such that…”
Section: Therefore (3)mentioning
confidence: 99%
“…The technique of the proof is inspired from [4]. We also discuss the Riesz decomposition theorem [32,Theorem 6] in quaternionic setting. More precisely, we prove that this decomposition is unique.…”
Section: Introductionmentioning
confidence: 99%
“…Let P [q] denote the corresponding Riesz projector with rang and kernel denoted by R(P [q] ) and N(P [q] ), respectively. Thanks to the Riesz decomposition theorem [34,Theorem 6] in quaternionic setting, we have…”
Section: Introductionmentioning
confidence: 99%