Structure of trans-dichlorobis(2-methylimidazole)palladium(II), [Pd(C4H6N2)2Cl2]

Abstract

188 trans-DICHLOROBIS( 1 -METHYLIMIDAZOLE)PALLADIUM (I I)unshared in the imidazole molecule. Since the electrons at N(3) are part of the aromatic sextet, the bonding of N(3) to a metal ion is disfavoured and although bonding of the imidazole ring to metal ions via C(2) has been reported recently (Sundberg, Brian, Taylor The molecules are held together solely by van der Waals forces. There are no significant intermolecular interactions; the packing diagram is shown in Fig. 2

Structure of trans-dichloro-cis-dichlorobis(1-propylimidazole)platinum(IV)

“…The structural parameters of the two independent imidazole rings are very similar and are well within the range observed in other metal complexes and derivatives (Navarro-Ranninger, Martinez-Carrera & Garcia-Blanco, 1983;Brouant, Barbe, Marsura & Luu-Duc, 1985). Both imidazole rings are planar; the propyl group is twisted as indicated by the torsion angles C(13)-N(12)-C(14)-C(15) = 80 (1) and C(23)-N(22)-C(24)-C(25) = 67 (2) °.…”

Crystal structure of trans-dichloro-bis[(E)-2-(1-methoxy-imidazol-2-yl)-2-oxoacetaldehyde O-methyl oxime]palladium(II), PdCl2(C7H9N3O3)2

“…The dihedral angle between the imidazole ring and the ligand plane is 47°. Similar trans-dichlorobis(imidazole)-Pd(II)( not counting benzimidazole) complexes have been reported previously [2][3][4][5][6][7][8][9][10][11][12][13]. However, complexes involving 1,2-disubstituted imidazole ligands seem to be rare [14][15][16][17].…”

A neutron diffraction study of bis(cyclopentadienyl)(methyl)(methylene)tantalum(V) at 15 K

“…The structural parameters of the two independent imidazole rings are very similar and are well within the range observed in other metal complexes and derivatives (Navarro-Ranninger, Martinez-Carrera & Garcia-Blanco, 1983;Brouant, Barbe, Marsura & Luu-Duc, 1985). Both imidazole rings are planar; the propyl group is twisted as indicated by the torsion angles C(13)-N(12)-C(14)-C(15) = 80 (1) and C(23)-N(22)-C(24)-C(25) = 67 (2) °.…”