Study of the (d, p) Reactions onZn64,66,68,

β-decay studies of the transitional nucleusCu75and the structure ofIlyushkin1, Winger2, Rykaczewski3 et al. 2011Phys. Rev. C16070View full textAdd to dashboardCite

“…The occurrence of a three-quasiparticle state seems the reasonable explanation since our data are consistent with a − and 9/2 + states in 75 Zn. Energy levels in zinc are taken from [5], [12], [13], and the present work. For discussion, see text.…”

“…1) indicate a lowering of the 5/2 − state relative to the 3/2 − ground state. Recently, a combination of in-source and collinear laser spectroscopy measurements of the hyperfine structure of 75 Cu revealed µ( 75 Cu) = +1.0062 (13)µ N corresponding to spin J = 5/2 for 75 Cu [6]. Additionally, both recently completed studies on β decay of 77 Cu [7,8] suggest 5/2 − for its ground state.…”

“…Prior to this study, the only data available on the β decay of 75 Cu included its half-life (1.224(3)s [10]) and delayed-neutron emission probability (3.5±0.6% [11]). Information concerning the low-lying levels of the odd-A zinc (Z = 30) isotopes with A = 67, 69, 71 is known from β-decay and (d, p) neutron transfer reaction studies [12,13]. The structure of 73 Zn was investigated with a multi-nucleon transfer reaction [14] as well as the β decay of 73 Cu produced in the fragmentation of a 76 Ge beam in a beryllium target [5].…”

“…Both the 7/2 + ground state and 9/2 + first excited state have been tentatively assigned in 77 Zn where the 9/2 + state lies ∼ 600 keV below the 1/2 − state [7]. Identifying the 1/2 − and 9/2 + states in 75 Zn shall complete the information on the evolution of shell structure near Fermi level [15], those in zinc from [5], [12], and [13]. For discussion, see text.…”

Introduction to the study of collisions between heavy nuclei

“…It has also heen argueJ that the gross~structure seen in ~he in- The spectroscopic factor S~j operator is the square of the matrix element of a neutron creation operator between the initial and final states s~j > [' L (15) and contains the nuclear structure information. The shape o:E the an- only one value of j (j =If) yields a non-zero value for S£j' and then parity conservation picks out a unique value from the pair t = j ±1/2.…”