2011
DOI: 10.7494/opmath.2011.31.1.75
|View full text |Cite
|
Sign up to set email alerts
|

Subadditive periodic functions

Abstract: Abstract. Some conditions under which any subadditive function is periodic are presented. It is shown that the boundedness from below in a neighborhood of a point of a subadditive periodic (s.p.) function implies its nonnegativity, and the boundedness from above in a neighborhood of a point implies it nonnegativity and global boundedness from above. A necessary and sufficient condition for existence of a subadditive periodic extension of a function f0 : [0, 1) → R is given. The continuity, differentiability of… Show more

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1
1
1
1

Citation Types

0
6
0

Year Published

2013
2013
2020
2020

Publication Types

Select...
7

Relationship

1
6

Authors

Journals

citations
Cited by 13 publications
(6 citation statements)
references
References 12 publications
0
6
0
Order By: Relevance
“…The leading order nonlinearity in the evolution equation for the α-FPUT is cubic; this implies three-wave interactions of the form 2 → 1, 1 → 2 or 3 → 0 (the latter have been already excluded). It is known, see for example [4,31], that the function f k = 2| sin(k/2)| is a subadditive function, i.e.…”
Section: Three-wave Resonant Interactions In the α-Fputmentioning
confidence: 99%
“…The leading order nonlinearity in the evolution equation for the α-FPUT is cubic; this implies three-wave interactions of the form 2 → 1, 1 → 2 or 3 → 0 (the latter have been already excluded). It is known, see for example [4,31], that the function f k = 2| sin(k/2)| is a subadditive function, i.e.…”
Section: Three-wave Resonant Interactions In the α-Fputmentioning
confidence: 99%
“…Subadditive and sublinear functions play a fundamental role in mathematics and so have attracted the interest of many authors (see e.g. [3], [5], [20], [27], [31], [33], [34], [42]). Examples of subadditive functions include norms, seminorms, and the function R ∋ x → √ |x| ∈ R (see e.g.…”
Section: Motivation and Auxiliary Resultsmentioning
confidence: 99%
“…Since f is even, it follows that f (1) = f (−1) ≤ 0. By Lemma 7 we deduce that f is 1-periodic, whence f (x) = f (−x) = f (1 − x) for every x ∈ [0, 1], so f satisfies (6). Now from Corollary 9 we see that f = T .…”
Section: Characterization Of the Takagi Function As A Subadditive Solmentioning
confidence: 85%