2017
DOI: 10.1017/apr.2016.83
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Subgeometric rates of convergence for Markov processes under subordination

Abstract: We are interested in the rate of convergence of a subordinate Markov process to its invariant measure. Given a subordinator and the corresponding Bernstein function (Laplace exponent) we characterize the convergence rate of the subordinate Markov process; the key ingredients are the rate of convergence of the original process and the (inverse of the) Bernstein function. At a technical level, the crucial point is to bound three types of moments (sub-exponential, algebraic and logarithmic) for subordinators as t… Show more

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Cited by 17 publications
(8 citation statements)
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“…The Nash type and super Poincaré inequalities have already been investigated in [2,21]. Recently, sub-exponential decay for subordinated semigroups was studied in [6], where φ ν is assumed to satisfy…”
Section: Preparationsmentioning
confidence: 99%
“…The Nash type and super Poincaré inequalities have already been investigated in [2,21]. Recently, sub-exponential decay for subordinated semigroups was studied in [6], where φ ν is assumed to satisfy…”
Section: Preparationsmentioning
confidence: 99%
“…Proof of Example Since S 2 has finite second moments, holds true. Since the characteristic exponent of S 2 is ϕ2false(ufalse)=c2β1Γfalse(1βfalse)()u+ρ1/ββρ, we obtain from [, Theorem 2.1 b)] that ES2(T)1Cβ,c2,ρT1/βT1=Cβ,c2,ρT1T11/β1,T>0,for some constant Cβ,c2,ρ>0. Inserting this bound, and into Corollary , the desired estimate follows.…”
Section: Proofs Of Theorem and Examples Andmentioning
confidence: 89%
“…Proof of Example By the self‐similar property of α‐stable subordinators, one has ES1(T)κ=Tκ/αES1(1)κ,T>0,κ>0.On the other hand, it is clear that ES2false(Tfalse)=TES2false(1false)<,T>0.Since e1normalefalse(1zfalse)1normalez1z for all z0, we get that for all u>00truefalse(0,1false)()1normaleuxx1β0.16emnormaldxu01xβ0.16emnormaldx=u1β.Here, fg means that c1ffalse(ufalse)gfalse(ufalse)cffalse(ufalse) for some constant c1 and all u>0. This, together with [, Theorem 3.8 (a)] (or [, Theorem 2.1 b)]), yields that for some constant Cβ…”
Section: Proofs Of Theorem and Examples Andmentioning
confidence: 91%
“…(28), can be expressed in terms of the characteristic exponent of (P t ) t≥0 and the Bernstein function g. Let us consider the following important example. In particular, µ t is absolutely continuous with respect to Lebesgue measure if, and only if, t ({0}) = 0; a sufficient condition is that g satisfies the Hartman-Wintner condition lim λ→∞ g(λ) log λ = ∞, 6 The vague topology is the weak * -topology in the space of (signed) Radon measures (Cc(R n )) * .…”
Section: 3mentioning
confidence: 99%