2019
DOI: 10.48550/arxiv.1904.06571
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Subquandles of free quandles

Sergei O. Ivanov,
Georgii Kadantsev,
Kirill Kuznetsov

Abstract: We prove that a subquandle of a free quandle is free.

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“…Proof. An analogue of the Nielsen-Schreier theorem stating that every subquandle of a free quandle is free has been proved recently in [13]. Let F Q 2 = x ⋆ y be the free quandle of rank two.…”
Section: Idempotents In Quandle Rings Of Free Productsmentioning
confidence: 99%
See 1 more Smart Citation
“…Proof. An analogue of the Nielsen-Schreier theorem stating that every subquandle of a free quandle is free has been proved recently in [13]. Let F Q 2 = x ⋆ y be the free quandle of rank two.…”
Section: Idempotents In Quandle Rings Of Free Productsmentioning
confidence: 99%
“…Adding(12) for all x ∈ X gives ε(v) = ε(v)ε(u). Similarly, adding(13) for all y ∈ Y gives ε(w) = ε(w)ε(u). If ε(u) = 0, then ε(v) = ε(w) = 0, and hence u = 0, a contradiction.…”
mentioning
confidence: 99%