2018
DOI: 10.1103/physrevmaterials.2.093602
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Substitution of Er, In, and Hf in LiNbO3 : Evidence for multiple defect distributions about dopant sites

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Cited by 4 publications
(3 citation statements)
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“…For the 0.1% Sn sample (Figure a), the amplitudes of the further neighbor peaks are quite large and the data can be well fit (solid orange line) to the hematite structure, with a small expansion for the Sn–Fe pairs compared to hematite, roughly 0.1 Å for closer pairs but only 0.02 Å for Fe neighbors near 3.7 Å. This is the expected behavior around a substitutional dopant site when the dopant valence Sn­(4+) is higher that the host valence Fe­(3+), and this behavior has been observed in other similar situations . The further neighbor Sn–O peaks are expected to contract very slightly, but because these small peaks overlap the larger Sn–Fe peaks, the pair distances fluctuate too much.…”
Section: Resultsmentioning
confidence: 66%
“…For the 0.1% Sn sample (Figure a), the amplitudes of the further neighbor peaks are quite large and the data can be well fit (solid orange line) to the hematite structure, with a small expansion for the Sn–Fe pairs compared to hematite, roughly 0.1 Å for closer pairs but only 0.02 Å for Fe neighbors near 3.7 Å. This is the expected behavior around a substitutional dopant site when the dopant valence Sn­(4+) is higher that the host valence Fe­(3+), and this behavior has been observed in other similar situations . The further neighbor Sn–O peaks are expected to contract very slightly, but because these small peaks overlap the larger Sn–Fe peaks, the pair distances fluctuate too much.…”
Section: Resultsmentioning
confidence: 66%
“…Since the ionic radius of In +3 being 80 pm is very close to that of Cu +2 (77 pm) and Cu +1 (60–96 pm), substitution of indium in vacant sites of Cu is possible. However, as the bond length of Cu—O (1.878 Å) is smaller than that of In—O (2.15 Å), formation of In 2 O 3 instead of CuO is still less probable. In this case, indium substitution weakens the Cu—O bonds, leading to easier atomic displacement, which may have resulted in the large grains observed in CIC samples.…”
Section: Resultsmentioning
confidence: 99%
“…The result verifies that the doped ions do not occupy interstitial positions in the lattice but enter the crystal lattice by replacing Li + or Nb 5+ ions. Since the radius of Er 3+ is larger than that of Li + and Nb 5+ ions, the cell size and shape will slightly change, which corresponds to the changes of the diffraction peaks in intensity.…”
Section: Resultsmentioning
confidence: 99%