1998
DOI: 10.1016/s0022-4049(96)00094-1
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Sufficient conditions for a group of automorphisms of a Riemann surface to be its full automorphism group

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Cited by 3 publications
(5 citation statements)
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“…From Theorem III.4, there exists a Riemann surface X such that X/H = Y and the involution of Y does not lift to an automorphism of X. If g = 3, this result, in conjunction with a theorem of [12], yields that H = Aut(X). We outline the analogous argument if g = 2.…”
Section: Theorem Iii5 Assume Y Is a Hyperelliptic Surface Of Genus mentioning
confidence: 94%
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“…From Theorem III.4, there exists a Riemann surface X such that X/H = Y and the involution of Y does not lift to an automorphism of X. If g = 3, this result, in conjunction with a theorem of [12], yields that H = Aut(X). We outline the analogous argument if g = 2.…”
Section: Theorem Iii5 Assume Y Is a Hyperelliptic Surface Of Genus mentioning
confidence: 94%
“…But in this case, we apply Proposition IV.3, which yields that x 2g+1 + 2H = x 1 + x 2 + · · · + x 2g + 2H. Thus, in this case also, H equals the union in (12), and there is no fixed point free lift. b) We now show that if 2 r−s > 2, then there exists a Riemann surface which admits H as a group of automorphisms which has a fixed point free lift of the hyperelliptic involution.…”
Section: Example Imentioning
confidence: 98%
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“…For example, the case of surfaces of low genus was carefully studied by Wiman [14] in the late 1800s. Wiman directly handled defining equations of the surfaces, as used also in [5], [12] and [13]. Similarly, the technique of Fuchsian groups was used in [4] to solve the problem for the family of hyperelliptic Riemann surfaces.…”
Section: Introductionmentioning
confidence: 99%