1946
DOI: 10.1002/9780470132333.ch49
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Sulfites and Pyrosulfites of the Alkali Metals

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Cited by 3 publications
(4 citation statements)
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“…The Raman spectrum of Na 2 SO 3 in its crystalline form is shown in Figure 6 . If sodium sulfite is allowed to crystallize from an aqueous solution at room temperature, it generates heptahydrate, [ 60 ] oxidizing in the air to form sulfates (SO 4 2− ) ions, so it is expected to detect some spectral features relative to sulfates [ 60 ].…”
Section: Resultsmentioning
confidence: 99%
“…The Raman spectrum of Na 2 SO 3 in its crystalline form is shown in Figure 6 . If sodium sulfite is allowed to crystallize from an aqueous solution at room temperature, it generates heptahydrate, [ 60 ] oxidizing in the air to form sulfates (SO 4 2− ) ions, so it is expected to detect some spectral features relative to sulfates [ 60 ].…”
Section: Resultsmentioning
confidence: 99%
“…Along with the newly synthesized heterocycle, other subproducts were formed. We think their presence was due to the degradative processes of compound 1, as already documented [95,105,106]. Hence, a short silica pad was made to obtain the desired product in high purity.…”
Section: Procedures Bmentioning
confidence: 87%
“…Firstly, it enables the formation of the active tautomer AIMS, as described by Dittmer [91] and Krug [92]. Secondly, the complete consumption of 1 to sodium sulphoxylate in a strong basic environment avoids other collateral processes such as the auto condensation of TDO to cyclic derivatives, as reported in the literature [95]. Thirdly, the presence of water might prevent the formation of other undesired redox intermediates, because it acts as a proton donor [96].…”
Section: Procedures Bmentioning
confidence: 87%
“…Nonetheless, we cannot completely rule out the presence of sodium dithionite and sodium bisulfite as reducing agents. The former can be formed by TDO degradation [38,94], and the sulfur dioxide may generate the latter in the presence of water [95]. Ultimately, adding fresh TDO to the reaction medium let the ring be closed to the corresponding aromatic heterocycle (Scheme 8, pathway 4).…”
Section: Procedures Bmentioning
confidence: 99%