2016
DOI: 10.1090/mcom/3129
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Sums of two $S$-units via Frey-Hellegouarch curves

Abstract: In this paper, we develop a new method for finding all perfect powers which can be expressed as the sum of two rational S-units, where S is a finite set of primes. Our approach is based upon the modularity of Galois representations and, for the most part, does not require lower bounds for linear forms in logarithms. Its main virtue is that it enables to carry out such a program explicitly, at least for certain small sets of primes S; we do so for S = {2, 3} and S = {3, 5, 7}.

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Cited by 8 publications
(8 citation statements)
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References 21 publications
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“…The above conjecture has been verified in some special cases (see [1,[10][11][12][13]15], [23] and [26]). But, in general, it is far from solved problem.…”
Section: Introductionmentioning
confidence: 79%
See 1 more Smart Citation
“…The above conjecture has been verified in some special cases (see [1,[10][11][12][13]15], [23] and [26]). But, in general, it is far from solved problem.…”
Section: Introductionmentioning
confidence: 79%
“…But, his proof is incorrect. Until 2017, M. A. Bennett and N. Billery [1] used the modular approach to solve the case k ∈ {12, 24}. It follows that the case 4 | k and 2k − 1 is an odd prime power is a very difficult case to Conjecture 1.1.…”
Section: Introductionmentioning
confidence: 99%
“…This class of equations contains in particular all equations considered in this paper. Here we mention that the possibility of solving certain cubic Thue-Mahler equations via modular symbols was already discussed in Bennett-Dahmen [BD13,§14], see also the recent works of Kim [Kim16] and Bennett-Billerey [BB16]. Our first type of algorithms is very fast for "small" parameters, since in this case we can use Cremona's database listing all elliptic curves over Q of conductor at most 350000 (as of August 2014).…”
Section: Algorithms Via Modular Symbolsmentioning
confidence: 99%
“…Suppose that l ∈ {2, 3}. In a recent work, Bennett-Billerey [BB16] show in particular how to practically solve the following problem (in which l = 2 is the original problem)…”
Section: Generalizedmentioning
confidence: 99%
“…This gives a bound on z independent of c. Recently, R. Scott and R. Styer [157] proved that if c ≡ 1 mod 2 then z < 1 2 ab. In some cases, finding a bound on z independent of c can be taken quite a bit further: when every prime dividing ab is in a given finite set of primes S, it is often possible to show that (1.1) implies z = 1 except for a finite list of specified exceptions; to do this, elementary methods sometimes suffice (e. g., S = {2, 3, 5}), but in general they do not, particularly when 2 ∈ S. M. A. Bennett and N. Billerey [3] deal with the case S = {3, 5, 7}, completely handling not only (1.1) but also the more general case in which A and B are S-units such that A + B = c z , z > 1.…”
Section: Introductionmentioning
confidence: 99%