2011
DOI: 10.1093/imrn/rnr028
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Surface Quotients of Hyperbolic Buildings

Abstract: Abstract. Let Ip,v be Bourdon's building, the unique simply-connected 2-complex such that all 2-cells are regular right-angled hyperbolic p-gons and the link at each vertex is the complete bipartite graph Kv,v. We investigate and mostly determine the set of triples (p, v, g) for which there exists a uniform lattice Γ = Γp,v,g in Aut(Ip,v) such that Γ\Ip,v is a compact orientable surface of genus g. Surprisingly, for some p and g the existence of Γp,v,g depends upon the value of v. The remaining cases lead to o… Show more

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Cited by 8 publications
(14 citation statements)
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“…For example, see [4] for surface subgroups of right-angled Artin groups or [2], where Calegari and Walker show, that a random group contains many quasiconvex surface subgroups. Existence of surface subgroups in right-angled hyperbolic buildings was shown in [5], and in hyperbolic buildings with 4-gonal apartments in [14]. Existence of surface subgroups in fundamental groups of higher-dimensional complexes is discussed, for example, in [6].…”
Section: Introductionmentioning
confidence: 99%
“…For example, see [4] for surface subgroups of right-angled Artin groups or [2], where Calegari and Walker show, that a random group contains many quasiconvex surface subgroups. Existence of surface subgroups in right-angled hyperbolic buildings was shown in [5], and in hyperbolic buildings with 4-gonal apartments in [14]. Existence of surface subgroups in fundamental groups of higher-dimensional complexes is discussed, for example, in [6].…”
Section: Introductionmentioning
confidence: 99%
“…Thus our results show that if the building associated to G is Bourdon's building, then for all q the Kac-Moody group G admits a cocompact lattice. Lattices in the full automorphism group of Bourdon's building have been studied by several authors (see, for instance, [12] and references therein).…”
Section: Theorem 1 Let G Be a Complete Kac-moody Group Of Rank N ≥ 2mentioning
confidence: 99%
“…, A i n are non-trivial, the fact that Γ has a surface subgroup follows from either Holt-Rees [15 Proof. The construction of Γ in Section 4.3 uses a simple complex of groups from Futer-Thomas [12], so that by the same arguments as in [12], the group Γ has a surface subgroup. Now suppose n ≥ 6 and that q is any power of a prime.…”
Section: Proof Of the Surface Subgroup Corollarymentioning
confidence: 99%
See 1 more Smart Citation
“…In fact this result was already known for n ≥ 5 (and it is straightforward to prove for n=3,4); however our proof is short and elementary. For n ≥ 5 the result is proved in Sang-hyun Kim's 2007 thesis [16,Theorem 3.6] using Van Kampen diagrams, and for n ≥ 6 another quite different proof is provided in [15,Corollary 1.3].…”
Section: Generalising Servatius Droms and Servatiusmentioning
confidence: 99%