“…Example 3.11. Following on from Example 3.8, we can compute 𝑉 (3,1) [3,3], a virtual character of 𝔖 10 : 𝑉 (3,1) [3, 3] = (−1) 0 ⋅ 𝑉 (6,1) [3] + (−1) 1 ⋅ 𝑉 (3,2,2) [3] + (−1) 2 ⋅ 𝑉 (3,1 4 ) [3] = 𝜒 (9,1) + 𝜒 (6,4) − 2𝜒 (6,2,2) + 2𝜒 (6,1 4 ) + 𝜒 (4,4,2) + 2𝜒 (3,2 3 ,1) − 𝜒 (3,2,2,1 3 ) − 𝜒 (3,3,2,1,1) + 𝜒 (3,1 7 ) .…”