Triruthenium complex 2 containing a perpendicularly coordinated 1‐pentyne ligand, which is one of the key intermediates of the reaction of triruthenium pentahydrido complex 1 with n‐pentane, reacts with benzene to yield μ3‐benzyne–μ3‐pentylidyne complex 5 by C–H bond activation. β‐H elimination form the μ3‐penytylidyne ligand occurred upon heating to yield μ3‐pentenylidene complex 6, which was followed by the formation of closo‐ruthenacyclopentadiene complex 8 by the connection of the two hydrocarbyl moieties placed on each face of the triruthenium plane with partial metal–metal bond breaking. Treatment of 8 with pressurized hydrogen resulted in exclusive liberation of n‐pentylbenzene, which is difficult to synthesize by conventional Friedel–Crafts alkylation. These sequential transformations correspond to the formation of linear alkylbenzene by the reaction of pentane with benzene on a trimetallic plane. (© Wiley‐VCH Verlag GmbH & Co. KGaA, 69451 Weinheim, Germany, 2009)