The mechanism for direct insertion of O2 in a toluene-solvated palladium−hydride bond (avoiding
palladium zero) has been elucidated using quantum mechanics (B3LYP/LACVP** with the PBF polarizable
continuum solvent model) for PdII((−)-sparteine)(Cl)(H) and the model compound PdII(bipyridine)(Cl)(H).
We find that the process involves (1) the abstraction of the hydrogen atom by triplet oxygen, (2) the formation
of a stable L2XPdIOOH triplet species, (3) a spin transition resulting in a stable L2XPdIIOOH singlet species,
and (4) the loss of H2O2 and completion of the catalytic cycle upon the addition of HX. The limitations
involved in the spin transition, the formation of the triplet PdI−OOH species and the stability of that triplet
species are all dependent on the presence of an H-bond acceptor cis to the hydride and the electronic
characteristics of the other ligands which may or may not stabilize the PdI species. Without this cis H-bond
acceptor and/or electron-withdrawing ligands that can stabilize PdI, the reaction will not proceed via the
palladium hydride insertion mechanism in a nonpolar environment.