“…Based on the analysis results of products, the comparison of electrode potentials and the relevant references, the reaction mechanism of CO 2 with NaBH 4 in alkalinity was proposed, as shown in Eqs. (6)- (15) [19][20][21]34,37,40,41], in which the production of HCOO À was deduced as four recycling reactions of BH i (OH) 4Ài À1 (i = 4, 3, 2, 1) and HCO 2 BH j (OH) 3Àj À1 (j = 3, 2, 1, 0). In liquid phase, soluble CO 2 primarily combined with OH À to form HCO 3 À that would participate in the following cycle reactions.…”