1993
DOI: 10.1007/bf01061008
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Tame and wild subspace problems

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Cited by 44 publications
(42 citation statements)
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“…In these cases C is tame; see [7,9] for a precise definition. In all other cases C is wild, and a classification of the indecomposable modules is regarded to be impossible.…”
Section: Remarks On Previous Workmentioning
confidence: 98%
“…In these cases C is tame; see [7,9] for a precise definition. In all other cases C is wild, and a classification of the indecomposable modules is regarded to be impossible.…”
Section: Remarks On Previous Workmentioning
confidence: 98%
“…On the other hand, it was proved in ([1], 4.2, 4.3) and ( [3], 9.1, 9.4) that the category mod A of representations of an arbitrary finite-dimensional algebra A over k coincides with the category of representations of a certain vectroid V in the following sense: There exists an injective indecomposable A -module P such that the category of all A -modules that do not contain P as a direct summand is epivalent to Rep V. In this case, all these submodules are cyclic, X i m x V(X,X), and ml X .... x = , mdimX is a triangular basis of X e V (see Lemma 1 ).…”
Section: A Triple ( Uf X) Consisting Of the Spaces U ~ Modk And X~ mentioning
confidence: 99%
“…Lemma 4 implies the following assertion: (1,1), (2,2), and (3,3) and is equal to implies that q0 is aproduct of basis morphisms; hence, M(q0) = eii + ejj and char(k) = 2.…”
Section: Existence Of a Multiplicative Basis For A Finitely Spaced Momentioning
confidence: 99%
“…A scalarly multiplicative basis is called normed if it satisfies the following condition: (Ra(a, a)), all steps of ~ are not higher than (2, 1) and (3,2). Since ~q~ ~ M (IPva(a, a) …”
Section: I E (S A))i-lm(a)\(~(a A))im(a) Is a Basis In M(a) It Imentioning
confidence: 99%
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