“…Similarly, for each selected Boolean variable value combination resulting in a false value of 3 For instance, assuming that the test case being constructed currently ends with method m k and constraint (m i , m j , p) has to be exercised, it might be less expensive to exercise (m k , #, true), that is the re-instantiation arc, followed by a path from # to m i (followed by m j ), than a path from m k to m i . 4 If three Boolean variables are involved in the predicate and values 0, 1, and 1 (for the three variables respectively) are selected according to the predicate criterion, the integer representation is 3 (0.2^2 + 1.2^1 + 1.2^0).…”