2012
DOI: 10.1007/s00454-012-9429-1
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The Art Gallery Theorem for Polyominoes

Abstract: We explore the art gallery problem for the special case that the domain (gallery) P is an mpolyomino, a polyform whose cells are m unit squares. We study the combinatorics of guarding polyominoes in terms of the parameter m, in contrast with the traditional parameter n, the number of vertices of P . In particular, we show that ⌊ m+1 3 ⌋ point guards are always sufficient and sometimes necessary to cover an m-polyomino, possibly with holes. When m ≤ 3n 4 − 4, the sufficiency condition yields a strictly lower gu… Show more

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Cited by 13 publications
(13 citation statements)
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“…Our first pair of results are analogous to the result that gives the minimum number of guards needed to see all of an n-tile polyomino [5]. The difference is that our guards are rooks or queens rather than points with standard vision.…”
Section: Our Resultsmentioning
confidence: 57%
See 1 more Smart Citation
“…Our first pair of results are analogous to the result that gives the minimum number of guards needed to see all of an n-tile polyomino [5]. The difference is that our guards are rooks or queens rather than points with standard vision.…”
Section: Our Resultsmentioning
confidence: 57%
“…The question is similar to the famous art gallery problem of Chvátal, in which b n 3 c guards are sufficient to see all points in an n-vertex polygon, and some polygons need this many guards [8]. The paper first introducing the art gallery problem for polyominoes showss that b nþ1 3 c guards are sufficient and sometimes necessary to see all points in an n-tile polyomino [5], and there are similar bounds for higherdimensional polycubes [24]. Different notions of vision are possible in art gallery problems.…”
Section: Introductionmentioning
confidence: 99%
“…Moreover, if all line segments in S are vertical or all are horizontal, then they cannot collectively guard the outer rectangle entirely. 2 In order to guard P entirely, we add one more orthogonal line segment C as follows: if all line segments in S are vertical (resp., horizontal), then C is the maximal horizontal (resp., the maximal vertical) line segment inside P that aligns the upper edge (resp., the right edge) of the smaller rectangle of P ; see the line segment e (resp., e ) in Figure 6. If the line segments in S are a combination of vertical and horizontal line segments, then C can be either e or e .…”
Section: N Of Integers and An Integer Kmentioning
confidence: 99%
“…The art gallery problem is well known in computational geometry, where the objective is to cover a geometric shape (e.g., a polygon) with the union of the visibility regions of a set of point guards while minimizing the number of guards. The problem's multiple variants have been examined extensively (e.g., see [1,15,17]) and can be classified based on the type of guards (e.g., points or line segments), the type of visibility model, and the geometric shape (e.g., simple polygons, orthogonal polygons [6], or polyominoes [2]).…”
Section: Introductionmentioning
confidence: 99%
“…Moreover, the problem was also shown to be NP-hard for orthogonal polygons [14]. Since then, the problem and its many variants have been studied extensively for different types of polygons (e.g., orthogonal polygons [14] and polyominoes [1]), different types of guards (e.g., points and line segments) and different visibility types. See the surveys by O'Rourke [13] or Urrutia [15] for a detailed history of the art gallery problem.…”
Section: Introductionmentioning
confidence: 99%