2003
DOI: 10.1016/s0921-4526(03)00430-7
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The basis of wavelets for a finite Heisenberg magnet

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Cited by 34 publications
(25 citation statements)
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“…Since the periodic boundary condition are assumed, the Hamiltonian (1) has the obvious translational symmetry (â N +1i =â 1i ), this means that one-particle Hamiltonian of the form (1) is completely diagonalized by a Fourier transformation [18] of the form…”
Section: The Symmetry Of the Systemmentioning
confidence: 99%
“…Since the periodic boundary condition are assumed, the Hamiltonian (1) has the obvious translational symmetry (â N +1i =â 1i ), this means that one-particle Hamiltonian of the form (1) is completely diagonalized by a Fourier transformation [18] of the form…”
Section: The Symmetry Of the Systemmentioning
confidence: 99%
“…Furthermore, the remaining basis for the sector with M = −1 can be obtained by replacing all pluses by minuses, and vice versa, in all electron configurations of Table 3. Table 3 contains four regular orbits , of the group C 4 , and thus consists of four elements, but Table 2, besides its eight regular orbits [22], contains two orbits which are doubly rarefied. The construction of the symmetry SU (2) (2), of elements of the group SU(2) × SU (2), which is applicable in the procedure of exact diagonalization of the one-dimensional Hubbard Hamiltonian will be used in this case.…”
Section: Diagonalizationmentioning
confidence: 99%
“…The state | denotes the element of the basis of wavelets [22], given as the appropriate Fourier transform performed on the orbit . …”
Section: Diagonalizationmentioning
confidence: 99%
“…One can easily show, using Bethe ansatz [10], that eigenstates of the Hamiltonian (2) in this subspace are translationally covariant and represent magnon excitation, therefore we call them one-magnon spin states. These states, known in the literature as the basis of wavelets [11], have the Bloch form…”
Section: Introductionmentioning
confidence: 99%