2001
DOI: 10.1007/pl00011099
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The Bethe lattice spin glass revisited

Abstract: So far the problem of a spin glass on a Bethe lattice has been solved only at the replica symmetric level, which is wrong in the spin glass phase. Because of some technical difficulties, attempts at deriving a replica symmetry breaking solution have been confined to some perturbative regimes, high connectivity lattices or temperature close to the critical temperature. Using the cavity method, we propose a general non perturbative solution of the Bethe lattice spin glass problem at a level of approximation whic… Show more

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Cited by 781 publications
(1,736 citation statements)
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References 34 publications
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“…We use a population dynamics method, as introduced in [26,27], and model the distribution P i→j (ψ i→j ) by a population of N vectors ψ i→j . To compute P i→j (ψ i→j ) knowing the P k→i (ψ k→i ) for all incoming k we perform the 1RSB recursion in eq.…”
Section: Appendix D: Numerical Methodsmentioning
confidence: 99%
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“…We use a population dynamics method, as introduced in [26,27], and model the distribution P i→j (ψ i→j ) by a population of N vectors ψ i→j . To compute P i→j (ψ i→j ) knowing the P k→i (ψ k→i ) for all incoming k we perform the 1RSB recursion in eq.…”
Section: Appendix D: Numerical Methodsmentioning
confidence: 99%
“…We start by reviewing the replica symmetric (RS) version of the cavity method [26,27] and its implications for the coloring problem. In the last part of the section we show when, and why, the RS approach fails.…”
Section: The Cavity Formalism At the Replica Symmetric Levelmentioning
confidence: 99%
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“…while the sequence (u γ 1 ,...,γr ) γr≥1 has distribution Ξ mr . Therefore, writing for simplicity 6) where ∼ means equality in distribution and where we introduced the notation…”
Section: Theorem 3 Suppose That (12) (13) and (14) Hold And H ′ Nmentioning
confidence: 99%
“…To write ϕ(0) in terms of these functions B and u, we observe that 6) using that Ek = αp in the last line. In the case when H ′ N (σ) = 0, it was proved in [9] (see Chapter 7, [10]) that for α small enough, lim N →∞ F N = Φ(ζ α ) = inf ζ Φ(ζ) where ζ α is the unique solution of the equation…”
Section: Introductionmentioning
confidence: 99%