“…According to the differences of the given example, it is supposed to be generated by adding one step after their 32-step distinguisher. Then, we study the given 33-step boomerang : 3, 4,5, 7,10, 12, 21, 22, 23, 28, 30, 32 E 0 : 13 F 0 : 13 G 0 : 13, 32 H 0 : 4,5,7,10,12,13,21,22,28,30,32 w 0 : 4, 5,7, 12, 20, 21, 22, 28, 30 w' 0 : 4, 5,7, 12, 20, 21, 22, 28, 30 SS1 0,10 = A 0,23 , SS1 0,20 = E 0,13 D 0,23 ≠ (A 0 ⊕ B 0 ⊕ C 0 ) 23 D 0,i ≠ SS2 0,i (i = 3, 10) D 0,i ≠ w' 0,i (i = 4, 5,7, 12, 21, 22, 28, 30) SS2 0,20 ≠ w' 0,20 H 0,13 ≠ (E 0 ⊕ F 0 ⊕ G 0 ) 13 H 0,i ≠ w 0,i (i = 4, 5,7, 12, 21, 22, 28, 30) H 0,10 ≠ SS1 0,10 , SS1 0,20 ≠ w 0,20 [17] and find some contradictions between the two differential characteristics.…”