2012
DOI: 10.1016/j.tcs.2012.02.029
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The complexity of approximately counting stable matchings

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Cited by 12 publications
(20 citation statements)
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“…Item (1) follows from Theorem 1 because counting stable matchings for is equivalent to counting downsets in R ( ), while the problem of counting downsets in posets is known to be #BIS-complete [12]. 2 In the case of -attribute preferences, Item (1) was also proven by Chebolu et al [5] for any ≥ 3. Our techniques give an alternate-arguably simpler-proof of this result, albeit for the weaker condition ≥ 6.…”
Section: Introductionmentioning
confidence: 88%
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“…Item (1) follows from Theorem 1 because counting stable matchings for is equivalent to counting downsets in R ( ), while the problem of counting downsets in posets is known to be #BIS-complete [12]. 2 In the case of -attribute preferences, Item (1) was also proven by Chebolu et al [5] for any ≥ 3. Our techniques give an alternate-arguably simpler-proof of this result, albeit for the weaker condition ≥ 6.…”
Section: Introductionmentioning
confidence: 88%
“…While the Gale-Shapley algorithm finds some stable matching efficiently, many computational tasks related to the SMP are known to be computationally hard, such as counting and sampling stable matchings [1,5,19,21] and finding "fair" stable matchings for various notions of fairness [6-8, 13, 18, 20, 22-24, 27, 29, 32]. For these problems, the intractability arises due to the underlying structure of the set of stable matchings.…”
Section: Introductionmentioning
confidence: 99%
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