1985
DOI: 10.1016/s0019-9958(85)80015-2
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The complexity of equivalence problems for commutative grammars

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Cited by 24 publications
(21 citation statements)
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“…We include the very recent result regarding unfixed alphabets [HH14] that inclusion for regular grammars over an unfixed alphabet is coNEXP hard; it is likely that the proof can be also adapted for universality. On the other hand, it is known from [Huy85] that inclusion and universality for context-free grammars over an unfixed alphabet is in coNEXP. For completeness, we also include N (the non-commutative case -note that the membership problem is actually a different problem in the non-commutative case, since we cannot encode long words succinctly with the length of the word in binary); these results are known from other sources ( [MS72], also see [HU79] for a reference).…”
Section: Complexity Resultsmentioning
confidence: 99%
“…We include the very recent result regarding unfixed alphabets [HH14] that inclusion for regular grammars over an unfixed alphabet is coNEXP hard; it is likely that the proof can be also adapted for universality. On the other hand, it is known from [Huy85] that inclusion and universality for context-free grammars over an unfixed alphabet is in coNEXP. For completeness, we also include N (the non-commutative case -note that the membership problem is actually a different problem in the non-commutative case, since we cannot encode long words succinctly with the length of the word in binary); these results are known from other sources ( [MS72], also see [HU79] for a reference).…”
Section: Complexity Resultsmentioning
confidence: 99%
“…This involves checking whether the Parikh Image of one regular language is (not) contained in the Parikh Image of another regular language. It is known that this problem can be solved in nondeterministic exponential time (NEXPTIME) [25]. Proposition 11.…”
Section: Upper Bound For Unrestricted Quiescent Consistencymentioning
confidence: 99%
“…A nondeterministic Turing Machine can solve this problem in PSPACE as follows. First, it guesses a run σ whose length is at 2 Cited in [25]. most the upper bound and checks that σ is end-to-end quiescent.…”
Section: Proposition 13mentioning
confidence: 99%
“…It follows that the equivalence problem of commutative context-free grammars is decidable, see also [10]. In fact, as shown in [16], the equivalence problem for both commutative context-free grammars and commutative rational expressions are solvable in nondeterministic exponential time. Thus, the equational theory of continuous idempotent commutative semirings is also decidable in nondeterministic exponential time.…”
Section: For Every µ-Term T There Exists a Rational Term R Such That mentioning
confidence: 99%