2000
DOI: 10.1016/s0377-2217(99)00262-3
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The edge-weighted clique problem: Valid inequalities, facets and polyhedral computations

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Cited by 47 publications
(26 citation statements)
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“…Actually, if y can assume any fractional value, then the separation problem for (8.iii) reduces to the Maximum Edge-Weighted Clique problem in undirected graphs. The latter is known to be an NP-hard problem (see [24]), leaving very little hope to solve the separation e ciently. When y is binary and no constraints of type (8).ii are violated, the situation changes drastically.…”
Section: Solution Algorithmmentioning
confidence: 99%
“…Actually, if y can assume any fractional value, then the separation problem for (8.iii) reduces to the Maximum Edge-Weighted Clique problem in undirected graphs. The latter is known to be an NP-hard problem (see [24]), leaving very little hope to solve the separation e ciently. When y is binary and no constraints of type (8).ii are violated, the situation changes drastically.…”
Section: Solution Algorithmmentioning
confidence: 99%
“…Obviously, TSF1-DecðG; P; p ¼ 1; KÞ belongs to NP. To prove its completeness, we use a reduction from MEWC, the Maximum EdgeWeighted Clique problem, which is NP-complete [10]. Consider an arbitrary instance I 1 of MEWC: given a complete edge-weighted graph G c = (V c , E c , w), where w : E c !…”
Section: With a Single Slavementioning
confidence: 99%
“…Recently, Macambira and De Souza [1996] presented the following class of facet-defining inequalities for CP n b that generalizes the cut inequalities. …”
Section: Remark 22 the Fact That The Inequalities In Proposition 2mentioning
confidence: 99%
“…. , w n ) ∈ R n , we define the quadratic knapsack polytope QKP n b (w) as the convex hull of those vectors (x, y) ∈ R n(n+1)/2 satisfying the conditions (3)- (6) together with the following knapsack generalization of (2): Tree inequalities were also considered by Macambira and De Souza [1996]. They combined a tree inequality with an (α, β)-inequality for α = 2 and β = 1, and showed that the resulting inequality is facet-defining if the underlying tree is a path.…”
Section: 2mentioning
confidence: 99%