1954
DOI: 10.1063/1.1740184
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The Effect of Channel Holes on the Force Exerted by Effusing Vapors

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Cited by 100 publications
(45 citation statements)
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“…1^/ and Volmer! !^' has subsequently been used by a large number of workg],g^ ( 15,16,(20)(21)(22)(23)(24)(25)(26)(27)(28)(29)(30)(31)(32)(33)(34) -jjj^g efforts of several of these workers are noteworthy with regard to the present work. Wessel!26) determined the vapor pressure of iron by employing effusion cells of quartz and alunaina suspended from a tungsten torsion wire in a graphite sheath furnace capable of operating at temperatures up to 1500°C.…”
Section: Experimental Techniquesmentioning
confidence: 78%
“…1^/ and Volmer! !^' has subsequently been used by a large number of workg],g^ ( 15,16,(20)(21)(22)(23)(24)(25)(26)(27)(28)(29)(30)(31)(32)(33)(34) -jjj^g efforts of several of these workers are noteworthy with regard to the present work. Wessel!26) determined the vapor pressure of iron by employing effusion cells of quartz and alunaina suspended from a tungsten torsion wire in a graphite sheath furnace capable of operating at temperatures up to 1500°C.…”
Section: Experimental Techniquesmentioning
confidence: 78%
“…where p is the vapour pressure, m the mass loss during the time t, W a the Clausing coefficient of the Knudsen-cell orifice (30) , a the area of the effusion orifice, R the gas constant, T the thermodynamic temperature, and M the molar mass of the studied compound. …”
Section: Resultsmentioning
confidence: 99%
“…The weighings were reproducible to within ±2·10 −6 g. The membrane for the effusion measurement of vapour pressure was a tantalum foil, thickness l = (0.021 ± 0.0041) mm. The area of the effusion orifice was a = (6.69 ± 0.01)·10 −3 · cm 2 ; the Clausing coefficient (30) W a = (0.986 ± 0.003) was found from the expression:…”
Section: Methodsmentioning
confidence: 99%
“…The enthalpy of sublimation was computed from the relation between pressure and temperature. The effusion orifice area, a, and the Clausing coefficient (22) W a were a = (4.44 ± 0.02) · 10 −4 cm 2 and W a = (0.943 ± 0.012).…”
Section: Methodsmentioning
confidence: 96%