2016
DOI: 10.1137/140981745
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The Erdös--Hajnal Conjecture for Long Holes and Antiholes

Abstract: International audienceErdös and Hajnal conjectured that for every graph $H$, there exists a constant $c_H$ such that every graph $G$ on $n$ vertices which does not contain an induced copy of $H$ has a clique or a stable set of size $n^{c_H}$. We prove that for every $k$ there exists $c_k>0$ such that every graph $G$ on $n$ vertices not inducing a cycle of length at least $k$ nor its complement contains a clique or a stable set of size at least $n^{c_k}$

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Cited by 21 publications
(35 citation statements)
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“…It can be noted that the family of left nebulae contains infinitely many tournaments with prime subtournaments that are neither galaxies nor constellations (see: [10] for a definition of the family of constellations). For example, take a tournament of 12 vertices {1, … , 12} and with the set of backward edges under ordering (1, … , 12) of the form: {(5, 1), (9, 1), (8,6), (11,6), (4, 2), (10, 3), (12, 7)}. Using that ordering, one can note that is a subtournament of a tournament from the class of left nebulae (see Figure 1).…”
Section: If Is Either a Left Or A Right Nebula Then {mentioning
confidence: 99%
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“…It can be noted that the family of left nebulae contains infinitely many tournaments with prime subtournaments that are neither galaxies nor constellations (see: [10] for a definition of the family of constellations). For example, take a tournament of 12 vertices {1, … , 12} and with the set of backward edges under ordering (1, … , 12) of the form: {(5, 1), (9, 1), (8,6), (11,6), (4, 2), (10, 3), (12, 7)}. Using that ordering, one can note that is a subtournament of a tournament from the class of left nebulae (see Figure 1).…”
Section: If Is Either a Left Or A Right Nebula Then {mentioning
confidence: 99%
“…Finally, the family of central nebulae contains infinitely many tournaments with prime subtournaments that are neither galaxies nor constellations. For example, take a tournament of twelve vertices {1, … , 12} and with the set of backward edges under ordering (1, … , 12) of the form: {(4, 1), (8,4), (5,3), (9,5), (6,2), (11,6), (10,7), (12,10)}. Using that ordering one can note that is a central nebula.…”
Section: If Is Either a Left Or A Right Nebula Then {mentioning
confidence: 99%
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