2013
DOI: 10.1007/s11856-012-0190-1
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The generating graph of finite soluble groups

Abstract: For a finite group G, let Gamma(G) denote the graph defined on the non-identity elements of G in such a way that two distinct vertices are connected by an edge if and only if they generate G. We prove that if G is soluble, then the non-isolated vertices of Gamma(G) belong to a unique connected component

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Cited by 22 publications
(30 citation statements)
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“…Proof. The statement is clearly true if γ is of kind (1) or (2). In the third case b 1 = a 1 · a 2 , so b 1 , a 1 = a 1 , a 2 = F.…”
Section: The Free Group Of Rankmentioning
confidence: 89%
See 1 more Smart Citation
“…Proof. The statement is clearly true if γ is of kind (1) or (2). In the third case b 1 = a 1 · a 2 , so b 1 , a 1 = a 1 , a 2 = F.…”
Section: The Free Group Of Rankmentioning
confidence: 89%
“…Let Γ * (G) be the subgraph of Γ(G) that is induced by all the vertices that are not isolated. In [2] it is proved that if G is a 2-generated finite soluble group, then Γ * (G) is connected. Later on in [4] the second author investigated the diameter of such a graph proving that if G is a finite soluble group then diam(Γ * (G)) ≤ 3.…”
mentioning
confidence: 99%
“…Such groups G have long been studied by means of the generating graph, whose vertices are the elements of G, the edges being the 2-element generating sets. The generating graph was defined by Liebeck and Shalev in [16], and has been further investigated by many authors: see for example [3,5,6,12,18,19,20,23] for some of the range of questions that have been considered. Many deep structural results about finite groups can be expressed in terms of the generating graph.…”
Section: Introductionmentioning
confidence: 99%
“…Let ∆(G) be the subgraph of Γ(G) that is induced by all of the vertices that are not isolated. In [4] it is proved that if G is a 2-generated soluble group, then ∆(G) is connected. In this paper we investigate the diameter diam(∆(G)) of this graph.…”
Section: Introductionmentioning
confidence: 99%
“…It follows from the proof of [4,Lemma 6] that the number, say φ G,N (X, k), of k-tuples (g 1 n 1 , . .…”
Section: Introductionmentioning
confidence: 99%