“…The solution corresponds to the object motion in a circle of radius r = |r 0 | with velocity v = tanh |ψ 0 |, zero apparent acceleration a, and nonzero gravitational acceleration g. Then Ω = Ω √ 1 − v 2 , Ω = v/r, and Ω = g/r. The attitude vector ϑ remains zero, and hence dϑ/dt = 0, but the object nevertheless measures the constant angular velocity ω = cosh ψ(cosh ψ − 1)Ω in its reference system, and 7) ωτ…”