2004
DOI: 10.1016/j.disc.2003.11.031
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The Hamilton–Waterloo problem: the case of Hamilton cycles and triangle-factors

Abstract: We discuss a special case of the Hamilton-Waterloo problem in which a 2-factorization of Kn is sought consisting of 2-factors of two kinds: Hamiltonian cycles, and triangle-factors. We determine completely the spectrum of solutions for several inÿnite classes of orders n.

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Cited by 31 publications
(62 citation statements)
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“…In fact this paper is completely dedicated to the case of the Hamilton-Waterloo problem with triangle-factors and exactly one Hamilton cycle. As noted in [9], this is the most difficult case of this problem. We will base our work on several recursive constructions as well as direct constructions for some small orders.…”
Section: Theorem 13 [9] Let N ≡ 3 (Mod 6) There Is a Solution To Thmentioning
confidence: 99%
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“…In fact this paper is completely dedicated to the case of the Hamilton-Waterloo problem with triangle-factors and exactly one Hamilton cycle. As noted in [9], this is the most difficult case of this problem. We will base our work on several recursive constructions as well as direct constructions for some small orders.…”
Section: Theorem 13 [9] Let N ≡ 3 (Mod 6) There Is a Solution To Thmentioning
confidence: 99%
“…So since s + r = n−1 2 it is then convenient to just give the number of Hamilton cycles r in the HW(r, s; n, 3) when determining the spectrum for this problem. The following two theorems are proven in [9]. Theorem 1.2 [9] (a) Let n = 6k + 3 and assume that k ≡ 1 (mod 3), then there is a solution to the Hamilton-Waterloo problem HW(r, s; n, 3) with triangle-factors and exactly r Hamilton cycles for every 0 ≤ r ≤ n−1 2 , except possibly when r = 1.…”
Section: Theorem 11 (Seementioning
confidence: 99%
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