2020
DOI: 10.1016/j.jctb.2020.01.003
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The hat guessing number of graphs

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Cited by 19 publications
(22 citation statements)
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“…Taking G = B d,n , we see that the spine of the book has exactly d vertices and is a vertex cover for G, so HG(B d,n ) = 1 + h(N d ) satisfies (2). For the lower bound, as h(N) = 1, it suffices to prove for d 2 that (vacuously, no value is 0-abundant), and that x ∈ N d is type-i if i is the smallest index such that x i is not i-abundant, and say x is type-0 if it is not type-i for any i ∈ [d].…”
Section: Booksmentioning
confidence: 99%
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“…Taking G = B d,n , we see that the spine of the book has exactly d vertices and is a vertex cover for G, so HG(B d,n ) = 1 + h(N d ) satisfies (2). For the lower bound, as h(N) = 1, it suffices to prove for d 2 that (vacuously, no value is 0-abundant), and that x ∈ N d is type-i if i is the smallest index such that x i is not i-abundant, and say x is type-0 if it is not type-i for any i ∈ [d].…”
Section: Booksmentioning
confidence: 99%
“…[19,20]). In this note, we study a particular hat puzzle on graphs introduced by Butler, Hajiaghayi, Kleinberg, and Leighton [5], which has attracted some recent interest in discrete mathematics [2,3,8,9,10,12,18].…”
Section: Introductionmentioning
confidence: 99%
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“…The hat-guessing numbers of graphs other than the complete graph have proven surprisingly difficult to compute. The value of HG(G) has been determined for trees [7], cycles [16], extremely unbalanced complete bipartite graphs [2], and certain tree-like degenerate graphs [11], but outside of these very specific families little is known. In this paper we add to this list of solved graphs almost all books and windmills, as well as the graph K 3,3 , which is in some sense the first "interesting" complete bipartite graph for this problem.…”
Section: Introductionmentioning
confidence: 99%
“…In the paper defining the hat-guessing game [7], it was proved that for large n, HG (K n,n ) = Ω(log log n). Later, Gadouleau and Georgiou [9] proved that Ω(log n) HG (K n,n ) n + 1, and most recently, Alon, Ben-Eliezer, Shangguan, and Tamo [2] improved the lower bound to HG (K n,n ) = Ω(n…”
Section: Introductionmentioning
confidence: 99%