1998
DOI: 10.1007/pl00004395
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The idempotency of the real spectrum implies the extension theorem for Nash functions

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Cited by 3 publications
(4 citation statements)
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“…Then, we wait ten years to really put everything in order and produce complete solutions. This final part of the story started with [RzSh], where the methods of Commutative Algebra were fetched to the stage, and finally the series [CoRzSh1], [CoRzSh2], [Qz2], [Qz3], [CoSh2], [CoRzSh3], which appeared from 1995 to 2001 and fixed everything.…”
Section: Brief History Of the Topicmentioning
confidence: 99%
See 1 more Smart Citation
“…Then, we wait ten years to really put everything in order and produce complete solutions. This final part of the story started with [RzSh], where the methods of Commutative Algebra were fetched to the stage, and finally the series [CoRzSh1], [CoRzSh2], [Qz2], [Qz3], [CoSh2], [CoRzSh3], which appeared from 1995 to 2001 and fixed everything.…”
Section: Brief History Of the Topicmentioning
confidence: 99%
“…It is instructive for our topic the way that gap was discovered. After [CoRzSh1], Quarez found ( [Qz2]) an argument that deduced extension from idempotency, by making the ideas in the compact case available in the non-compact one. This lead to a protocolary revision of the quoted articles on idempotency, and to the unexpected finding that the proofs were incomplete.…”
Section: Abstract Nash Functionsmentioning
confidence: 99%
“…It was claimed in [Ro] that the idempotency was true for every commutative ring A, but the proof contained a gap. On the other hand, it was proved in [Qu1] that the idempotency would give a rather direct proof of the Extension theorem for Nash manifolds over the reals, both compact and noncompact. In this discussion, [Qu1] shows also that the Artin-Mazur property implies the idempotency for arbitrary rings, and consequently we can now conclude (Section 7) that idempotency holds for every commutative ring.…”
Section: Theorem 3 (Extension) Let I Be An Ideal Of N (ω) Then Everymentioning
confidence: 99%
“…On the other hand, it was proved in [Qu1] that the idempotency would give a rather direct proof of the Extension theorem for Nash manifolds over the reals, both compact and noncompact. In this discussion, [Qu1] shows also that the Artin-Mazur property implies the idempotency for arbitrary rings, and consequently we can now conclude (Section 7) that idempotency holds for every commutative ring. This is a big detour to prove the idempotency of the real spectrum, and in some sense goes in the unexpected direction, but so far there is no other approach that we know.…”
Section: Theorem 3 (Extension) Let I Be An Ideal Of N (ω) Then Everymentioning
confidence: 99%