2013
DOI: 10.1016/j.disc.2012.07.023
|View full text |Cite
|
Sign up to set email alerts
|

The minimum size ofk-rainbow connected graphs of given order

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
4

Citation Types

0
4
0

Year Published

2013
2013
2021
2021

Publication Types

Select...
5
1

Relationship

0
6

Authors

Journals

citations
Cited by 6 publications
(4 citation statements)
references
References 1 publication
0
4
0
Order By: Relevance
“…For n/2 < k, this theorem coincide with Theorem 1.1. As mentioned before, the case k = 3 has been already proved by Bode and Harborth [1], but our proof is different and shorter.…”
Section: Introductionmentioning
confidence: 61%
See 1 more Smart Citation
“…For n/2 < k, this theorem coincide with Theorem 1.1. As mentioned before, the case k = 3 has been already proved by Bode and Harborth [1], but our proof is different and shorter.…”
Section: Introductionmentioning
confidence: 61%
“…where the lower bound is due to Li et al [3] and the upper bound is due to a construction of Bode and Harborth [1]. When k = 3, Bode and Harborth [1] showed that t(n, 3) is actually equal to the upper bound for n ≥ 3. In this note, we show that the same statement holds for all n, k ≥ 3.…”
Section: Introductionmentioning
confidence: 98%
“…[1,14,15,20]. Extremal problems have been studied in [3,21,30,33]. Vertex-rainbow connection number was introduced by Krivelevich and Yuster [19].…”
Section: Introductionmentioning
confidence: 99%
“…Problem 1 for k = 1 was first considered by Schiermeyer [19], when he determined the values of t 1 (n, r) for n 2 ≤ r ≤ n − 1, and the asymptotic answer for r = 2. Subsequently, Bode and Harborth [2], and Li et al [12] made some improvements, and Lo [17] determined the values of t 1 (n, r) for 3 ≤ r < n 2 . Thus Problem 1 is essentially completely solved for k = 1.…”
Section: Introductionmentioning
confidence: 99%