2016
DOI: 10.1016/j.aim.2016.05.001
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The number of C2-free graphs

Abstract: One of the most basic questions one can ask about a graph H is: how many H-free graphs on n vertices are there? For non-bipartite H, the answer to this question has been well-understood since 1986, when Erdős, Frankl and Rödl proved that there are 2 (1+o(1))ex(n,H) such graphs. For bipartite graphs, however, much less is known: even the weaker bound 2 O(ex(n,H)) has been proven in only a few special cases: for cycles of length four and six, and for some complete bipartite graphs.For even cycles, Bondy and Simo… Show more

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Cited by 63 publications
(131 citation statements)
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“…We note that Morris-Saxton [17] obtained a result of a very similar flavor to our above result for p < 9 16 . They proved (among others) that if n −1/3 log 4 n ≤ p = o(1) then the largest C 4 -free subgraph of the random graph has at most C √ pn 3/2 edges whp.…”
Section: ⊓ ⊔supporting
confidence: 72%
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“…We note that Morris-Saxton [17] obtained a result of a very similar flavor to our above result for p < 9 16 . They proved (among others) that if n −1/3 log 4 n ≤ p = o(1) then the largest C 4 -free subgraph of the random graph has at most C √ pn 3/2 edges whp.…”
Section: ⊓ ⊔supporting
confidence: 72%
“…graphs H. When the order of magnitude of ex(n, H) is known then the situation is better: see [5] and [6] for when H is a complete bipartite graph, and see [17] for when H is an even cycle.…”
Section: Denote the Set Of Win Vertices By Wmentioning
confidence: 99%
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“…One might still ask whether the argument of could be adapted to our setting. As in most applications of the containers method, the heart of is proving a sufficiently strong supersaturation result for copies of C2h in n‐vertex graphs with more that Dn1+1/h edges; see [, Theorem 1.5].…”
Section: Discussionmentioning
confidence: 99%
“…Note that in general for the container method to work one needs some type of supersaturation, which means that if vertex set U is a somewhat larger than the independence number of the hypergraph, then U contains many hyperedges. Here we need a little bit more, we need some even distribution of these hyperedges, a similar obstacle (which was handled differently) showed up in [7].…”
Section: Introductionmentioning
confidence: 99%