1980
DOI: 10.1016/0005-2728(80)90031-6
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The one-electron reduction potentials of NAD

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Cited by 70 publications
(34 citation statements)
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“…The proposed scheme in Fig. 2 (48). When the basal system is perturbed to allow some IN⅐NAD synthesis in the presence of SOD, other radical species must replace O 2 .…”
Section: Discussionmentioning
confidence: 99%
“…The proposed scheme in Fig. 2 (48). When the basal system is perturbed to allow some IN⅐NAD synthesis in the presence of SOD, other radical species must replace O 2 .…”
Section: Discussionmentioning
confidence: 99%
“…The MPO\H # O # system catalysed the one-electron oxidation of tyrosine to tyrosyl radical which, in turn, rapidly oxidized NADPH (Scheme 1). Transient tyrosyl radicals are known to oxidize pyridine nucleotides by a direct one-electron transfer process [k l (6-8)i10( M −" :s −" ] [41], which results in the formation of NAD(P)d radical, a potent reductant [E m,( of NAD(P) + \NAD(P)d l k920 mV] [42]. Subsequently, the nucleotide radical is capable of rapidly reducing molecular oxygen (k l 2i10* M −" :s −" ) [ In contrast, results presented here on the guaiacolmediated NADPH oxidation suggest that a radical did not react with NADPH.…”
Section: Discussionmentioning
confidence: 99%
“…Indeed, the semiquinone flavin intermediate state need not even be entirely stable, as long as stability product (product of the NADH and flavin stability constants) is no smaller than 10 ñ20 , to achieve the millisecond rates often observed for these proteins. Using the reported aqueous NAD/NAD + redox couple of ñ0.92V (Farrington et al, 1980), we estimate an aqueous stability constant of NAD + /NADH of about 10 ñ20 . Thus, even a small amount of stabilization of the NAD radical intermediate by the protein will permit unstable flavin radical intermediates to be used.…”
Section: Cluster Examplesmentioning
confidence: 99%