2005
DOI: 10.1051/ita:2005009
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The perfection and recognition of bull-reducible Berge graphs

Abstract: The recently announced Strong Perfect Graph Theorem states that the class of perfect graphs coincides with the class of graphs containing no induced odd cycle of length at least 5 or the complement of such a cycle. A graph in this second class is called Berge. A bull is a graph with five vertices x, a, b, c, d and five edges xa, xb, ab, ad, bc. A graph is bull-reducible if no vertex is in two bulls. In this paper we give a simple proof that every bull-reducible Berge graph is perfect. Although this result foll… Show more

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Cited by 2 publications
(7 citation statements)
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“…If h ∈ W , this is by the definition of T . If h ∈ P ∪ X ∪ Y and t ∈ A this is by (4), (5) and (6). If h ∈ P ∪ X ∪ Y and t ∈ T − Y − A this is by the definition of Y .…”
Section: Some Lemmasmentioning
confidence: 99%
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“…If h ∈ W , this is by the definition of T . If h ∈ P ∪ X ∪ Y and t ∈ A this is by (4), (5) and (6). If h ∈ P ∪ X ∪ Y and t ∈ T − Y − A this is by the definition of Y .…”
Section: Some Lemmasmentioning
confidence: 99%
“…Suppose that u misses v. Consider any path R uv = r 1 -· · ·-r p given by (7), with p odd, r 1 = u, r p = v. Then v-c 1 -c 2 -u-R uv -v is an odd cycle of length at least five, so it must contains a triangle, for otherwise it contains an odd hole. Note that c 1 and c 2 do not see two consecutive vertices on the path R uv , since they are in Z * 2 and by (5). So, in order to have a triangle, there must be a vertex r j that sees both c 1 , c 2 , and so r j ∈ L 1 , and so 3 ≤ j ≤ p − 2.…”
Section: Transitive Orientationsmentioning
confidence: 99%
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