1952
DOI: 10.1021/j150494a006
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The Periodic Law in Mathematical Form.

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Cited by 12 publications
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“…It is in order to understand these that we try to improve and systematize our understanding of atoms. This is where the periodic system comes in; it has been called "without doubt the most important generalization in chemistry" (Hakala [29]). Attempts to construct a table for diatomic molecules have been made (Hefferlin et al [30]) with some success.…”
Section: Discussionmentioning
confidence: 99%
“…It is in order to understand these that we try to improve and systematize our understanding of atoms. This is where the periodic system comes in; it has been called "without doubt the most important generalization in chemistry" (Hakala [29]). Attempts to construct a table for diatomic molecules have been made (Hefferlin et al [30]) with some success.…”
Section: Discussionmentioning
confidence: 99%
“…At the same time, the numerous studies of this kind and the wide variety of approaches used indicate that this problem has not yet been adequately resolved. [30][31][32][33][34] It has been repeatedly noted 6 that a serious obstacle that makes it difficult to establish the quantitative form of the periodic law is the diversity and heterogeneity of various physical and chemical properties of elements. Indeed, if the argument of the desired quantitative form of the periodic dependence, of course, should be the charge of the atomic nucleus (i.e.…”
Section: Introductionmentioning
confidence: 99%
“…At the same time, the numerous studies of this kind and the wide variety of approaches used indicate that this problem has not yet been adequately resolved. 30–34…”
Section: Introductionmentioning
confidence: 99%
“…Then the [n + l, n]-rule with help of four actions of arithmetic and well known formulas k=n k=1 k = (1/2)n(n + 1), k=n k=1 k 2 = (1/6)n(n + 1)(2n + 1), leads to the Klechkovski-Hakala formulas [11,15] Z n+l = K(n + l) + 1, n+l Z = K(n + l + 1), Z n,l = K(n + l + 1) − 2(l + 1) 2 + 1, n,l Z = K(n + l + 1) − 2l 2 , Z n = K(n + 1) − 1, n Z = K(2n) − 2(n − 1) 2 = (1/6) (2n − 1) 3 + 11(2n − 1) , Z l = K(2l + 1) + 1 = (1/6) (2l + 1) 3 + (5 − 2l) , Z nr = K(n r + 2) − 1.…”
Section: Introductionmentioning
confidence: 99%