2013
DOI: 10.1002/nla.1886
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The perturbation bound for the Perron vector of a transition probability tensor

Abstract: SUMMARYIn this paper, we study the perturbation bound for the Perron vector of an mth‐order n‐dimensional transition probability tensor scriptPMathClass-rel=(pi1MathClass-punc,i2MathClass-punc,MathClass-op…MathClass-punc,im) with pi1MathClass-punc,i2MathClass-punc,MathClass-op…MathClass-punc,im⩾0 and MathClass-op∑i1MathClass-rel=1npi1MathClass-punc,i2MathClass-punc,MathClass-op…MathClass-punc,imMathClass-rel=1. The Perron vector x associated to the largest Z‐eigenvalue 1 of scriptP, satisfies scriptPbold-itali… Show more

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Cited by 26 publications
(12 citation statements)
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“…A Perron vector can be used for co-ranking schemes [11,14] for objects and relations in multi-relational or tensor data, and higher-order Markov chains [4,9,10].…”
Section: Theorem 13 Supposementioning
confidence: 99%
“…A Perron vector can be used for co-ranking schemes [11,14] for objects and relations in multi-relational or tensor data, and higher-order Markov chains [4,9,10].…”
Section: Theorem 13 Supposementioning
confidence: 99%
“…From tensors having found their way into many applications [15][16][17][18], a considerable amount of research has been carried out on tensor eigenvalues and its decompositions (for example, refer to [19][20][21][22]). Multiplication of tensors by vectors or matrices has been defined and used extensively (especially for eigenvalue problems) in literature [23][24][25][26][27][28], but there are far fewer indications of a kind of product that involves two tensors and the result of the operation be another tensor with the same dimensions of multipliers. In this paper, we define a sort of this rarely seen multiplication and show that it can be used and is in harmony with high-order Markov chains.…”
Section: Introductionmentioning
confidence: 99%
“…At present, the tensor eigenvalue problem becomes a hot topic because of its applications in diffusion tensor imaging, higher order Markov chains and data mining et al, see e.g. [1][2][3][4][5][6][7][8][9][10][11][12][13]. Below is the definition of eigenvalues of tensors.…”
Section: Introductionmentioning
confidence: 99%